40-10x^2/x^2+4^2

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Solution for 40-10x^2/x^2+4^2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4^2-((10*x^2)/(x^2))+40 = 0

4^2-10+40 = 0

46 = 0

x belongs to the empty set

x belongs to the empty set

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